Replace elements of sparse matrix from a full matrix.

Dear Experts
I have a huge matrix, M with zeros. I am converting M into sparse using sparse(M). After, I want to replace few positions (idx) of M from other matrix, N. I am using the following: M(idx) = N(idx). But, this is very very slow. Also MATLAB warns: This sparse indexing expression is slow. How I can do the above task?
Thanks in advance.

2 个评论

[19647672 60] is the size at present am dealing with. It may be more in future.

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回答(1 个)

What don't you replace the elements before converting it?

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No...I want to replace in sparse matrix. Actually I am using svds for M. M is huge.
I don't get it. You do start off with a full matrix M which you convert using sparse, don't you?
Yes..I am starting with a full matrix which has lot of zero's. Then converting it to sparse for svds. And after I have to replace certain zeros of sparse with the result obtained from svds.
If you know you are replacing zeros, then you can sparse() up the values that are going in as a second sparse matrix, and add that to the first sparse matrix.
Hi Walter..happy to see you. Yes I tried it, but replacing the values is taking hell lot of time.
When you create your original sparse matrix, be sure to allow extra nzmax; see http://www.mathworks.com/help/matlab/ref/spalloc.html
Actually my original matrix has zeros and I want to fill these zeros with numbers later...
Then spalloc() would be appropriate. If you create a matrix without using it or equivalent then you end up doing a lot of sparse reallocations as you add in new values.

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