minimum of a function
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Hello sir;
i am trying to find minimum of a function by putting more than one vectors in a single step to get a constant cost value.
bk=magic(4)=[16 2 3 13
5 11 10 8
9 7 6 12
4 14 15 1]
function=bk1'*H1'*H1*bk1-2*yr'*H1*bk1;
where yr is a column vector, H1 is a square matrix and bk1 is a column of bk.
i want to put each vector of bk in above function and select the minimum value in a single command.
i tried this one but it doesn't works.
[cost_value, indx]=min(abs(bk(:,[1:end])'*H1'*H1*bk(:,[1:end])-2*yr'*H1*bk(:,[1:end])));
please help
3 个评论
John D'Errico
2016-3-6
编辑：John D'Errico
2016-3-6
As you wrote it, that is not a function. It is an expression. Also, you cannot use the name "function" for a variable name.
If you are trying to find a minimum of a function, use an optimizer. Min is not an optimizer. Tools like fminsearch, fminunc, fmincon are optimzers.
Arif Ullah khan
2016-3-6
Arif Ullah khan
2016-3-6
采纳的回答
Image Analyst
2016-3-6
What is bk1 and H?
Anyway, why not just assign it to a numerical array and use min:
f =bk1'*H1'*H1*bk1-2*yr'*H1*bk1
[minFValue, linearIndexAtMinFValue] = min(f(:));
or
[rowAtMin, colAtMin] = find(f == min(f(:)))
2 个评论
Arif Ullah khan
2016-3-6
编辑：Arif Ullah khan
2016-3-6
Image Analyst
2016-3-6
Yep, my code will do it.
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