minimum of a function

1 次查看（过去 30 天）
Arif Ullah khan
Arif Ullah khan 2016-3-6
评论： Image Analyst 2016-3-6
Hello sir;
i am trying to find minimum of a function by putting more than one vectors in a single step to get a constant cost value.
bk=magic(4)=[16 2 3 13
5 11 10 8
9 7 6 12
4 14 15 1]
function=bk1'*H1'*H1*bk1-2*yr'*H1*bk1;
where yr is a column vector, H1 is a square matrix and bk1 is a column of bk.
i want to put each vector of bk in above function and select the minimum value in a single command.
i tried this one but it doesn't works.
[cost_value, indx]=min(abs(bk(:,[1:end])'*H1'*H1*bk(:,[1:end])-2*yr'*H1*bk(:,[1:end])));
please help
  3 个评论
显示 1更早的评论
Arif Ullah khan
Arif Ullah khan 2016-3-6
thnx for reply how but can i implement this to get the minimum value as well the index of the vector which gives the minimun value
Arif Ullah khan
Arif Ullah khan 2016-3-6
actually i want to find the column of bk which gives minimum value for the expression

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Image Analyst
Image Analyst 2016-3-6
What is bk1 and H?
Anyway, why not just assign it to a numerical array and use min:
f =bk1'*H1'*H1*bk1-2*yr'*H1*bk1
[minFValue, linearIndexAtMinFValue] = min(f(:));
or
[rowAtMin, colAtMin] = find(f == min(f(:)))
  2 个评论
Arif Ullah khan
Arif Ullah khan 2016-3-6
编辑：Arif Ullah khan 2016-3-6
bk1 is each column of bk matrix while H1 is a square matrix actually i want to find the column of bk which gives minimum value for the expression
Image Analyst
Image Analyst 2016-3-6
Yep, my code will do it.

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Linear Programming and Mixed-Integer Linear Programming 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by