Is it possible to find corresponding row from other matrix's row??

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Triveni
Triveni 2016-3-8
评论： Triveni 2016-3-9
y = [ 90 90 -45 0 0 45 45 0 -45 15 15;
90 90 -45 0 0 45 45 0 -45 15 15;
90 90 -45 0 0 45 45 0 -45 15 0;
90 90 -45 0 0 45 45 0 -45 15 0;
90 90 -45 0 0 45 45 0 -45 15 15;
90 90 -45 0 0 45 45 0 -45 15 15;];
y0 = sort(y,2);
y = y(sum([ones(size(y,1),1),diff(y0,[],2)~=0],2) >= numel(unique(y)),:);
y = permute(y ,[3 2 1]);
for k = 1:size(y,3)
[x0(:,:,k), x00(:,:,k)] = hist(y(:,:,k), unique(y(:,:,k)));
end
x0 =permute(x0,[3 2 1]); x00 =permute(x00,[3 2 1]);
x0(any(x0<2,2),:) = [];
I have to find corresponding row of "x00"

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采纳的回答

Stephen23
Stephen23 2016-3-9
编辑：Stephen23 2016-3-9
It is easy, you just need to assign the logical conditions to an index variable. So instead of this:
x0(any(x0<2,2),:) = [];
you should allocate that logical condition to a variable:
idx = any(x0<2,2);
and then you can use idx for any of the matrices:
>> xdel = x0(idx,:)
xdel =
2 4 1 2 2
2 4 1 2 2
>> xnew = x0(~idx,:)
xnew =
2 3 2 2 2
2 3 2 2 2
2 3 2 2 2
2 3 2 2 2
and now you can try x00(idx,:) and x00(~idx,:) yourself!
  2 个评论
Triveni
Triveni 2016-3-9
y = [ 90 90 -45 0 0 45 45 0 -45 15 15;
90 90 -45 0 0 45 45 0 -45 15 15;
90 90 -45 0 0 45 45 0 -45 15 0;
90 90 -45 0 0 45 45 0 -45 15 0;
90 90 -45 0 0 45 45 0 -45 15 15;
90 90 -45 0 0 45 45 0 -45 15 15;];
y0 = sort(y,2);
y = y(sum([ones(size(y,1),1),diff(y0,[],2)~=0],2) >= numel(unique(y)),:);
y = permute(y ,[3 2 1]);
for k = 1:size(y,3)
[x0(:,:,k), x00(:,:,k)] = hist(y(:,:,k), unique(y(:,:,k)));
end
x0 =permute(x0,[3 2 1]); x00 =permute(x00,[3 2 1]);
y = permute(y ,[3 2 1]);
idx = any(x0<2,2);
xdel = x0(idx,:)
xnew = x0(~idx,:)
y = y(~idx,:)

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更多回答（1 个）

Ced
Ced 2016-3-8
编辑：Ced 2016-3-8
I am not sure I understood the full question, but in short, you want to delete rows in which there is an element < 2 ? You basically already answered the question. Since you like one liners, I think this should do the trick:
x(any(x<2,2),:) = [];
This finds all rows (DIM 2) in which there is ANY element smaller than 2, selects these rows, and deletes them.
If you want to match your centers, you can do:
rows_del = any(x<2,2);
x(rows_del,:) = [];
z(rows_del,:) = [];

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