Is it possible to use 'numel' in nested struct?

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Hi! I use numel in a nested struct:
for i=1:9
for j=1:size(E(1,i).bcd,2)
for jj=1:numel(E(1,i).bcd{1,j}.b)
if(isempty(E(1,i).bcd{1,j}.b{jj}))
E(1,i).bcd{1,j}.b{jj}=''
end
end
end
end
but it gives this error
'Attempt to reference field of non-structure array.'
Is it possible that the error is in the use of numel? thanks

采纳的回答

Guillaume
Guillaume 2016-3-9
编辑:Guillaume 2016-3-9
No, the error has nothing to do with numel. As the error says, you're attempting to access a field (b maybe) of something that is not a structure.
Assuming that E is really a structure. One of the cell array in the bcd fields does not contain a structure.
To check
for eidx = 1:numel(E)
for bcdidx = 1:numel(E(eidx).bcd)
if ~isstruct(E(eidx).bcd{bcdidx})
warning('E(%d).bcd{%d} is not a structure', eidx, bcdidx);
end
end
end
  2 个评论
pamela sulis
pamela sulis 2016-3-9
I try your code and I have an other error: 'Scalar index required for this type of multi-level indexing'. Thanks for your suggestion: surely there is an error in the dimensions of the struct or in the definition of the struct.
Guillaume
Guillaume 2016-3-9
I did make a typo in my code (used idx instead of eidx, most likely you already had a idx variable in your workspac). I've fixed it now and the code should run without error.
The problem is most likely that one of your cell array bcd is empty.

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