clc
A = input('Opposite angle: ');
B = input('Adjacent angle: ');
C = input('Hypotenuse angle: ');
E = (B/C); %Cosine
F = (A/C); %Sine
%S(o/h)C(a/h)T(o/a) SoaCahToa
T = menu ('Which trig sign do you want to use.' ,'sin', 'cos', 'tan', 'cot', 'cosec', 'sec');
if T == 1;
(A/C)
elseif T == 2;
(B/C)
elseif T == 3;
(A/B)
elseif T == 4;
(B/A)
elseif T == 5
(C/A)
elseif T ==6
(C/B)
end
X = sprintf(('For a triangle of sides H, O and A,(Needs to be the answer picked from menu)
Does anyone know how once I pick from the menu, to make that answer a variable so I can use for sprintf like %s or something. Would be a huge help.

 采纳的回答

Use a cell array of strings. You can address the as any other array.
For example:
fcn_name = {'sin', 'cos', 'tan', 'cot', 'cosec', 'sec'};
T = 3;
str = sprintf('The value of %s = %.4f\n', fcn_name{T}, 0.3)
str =
The value of tan = 0.3000

更多回答(0 个)

类别

帮助中心File Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by