Deleting elements in cell array constrained by logic

2016 3 10
1 个回答
回答已采纳
更新时间：2016 3 24
2 次查看（30 天）

0 个投票

I have a cell array for example: A = [{4,2,5},{3,5,7},{2,3,8,},{4,5,6}]. The elements in the cell array are time points in a time series from 0 to 10. I have a binary vector such as B = (0,0,0,1,1,0,0,0,0,0,0), which contains 10 elements (same as the size of the time series). I want to then remove any element in A that corresponding to a "1" in B, in other words remove all the 4s and 5s, to get a new cell array: A_new = [{2},{3,7},{2,3,8,},{6}]. Can anyone help? Thanks!

1 个评论
显示 -1更早的评论 隐藏 -1更早的评论

alicia che
alicia che 2016-3-24
I have an additional problem related to this- I have another cell array C that matches A: A represents onset time points and C are offset time points of the events. When I deleted entries in A with the constrain B, how can I delete those corresponding entries in C? I tried to use A to constrain C, but after the first round of deleting from A, the size changed and the entries in A and C no longer correspond to each other, which is a problem for me...Thanks for helping!!

请先登录，再进行评论。

请先登录，再回答此问题。

 采纳的回答

Fangjun Jiang
Fangjun Jiang 2016-3-10
编辑：Fangjun Jiang 2016-3-10

0 个投票

B = [0,0,0,1,1,0,0,0,0,0,0];
A = {[4,2,5],[3,5,7],[2,3,8],[4,5,6]};
NewA=cellfun(@(x) x(~ismember(x,find(B))),A,'uni',false)
% a more readable version would be
TP=find(B);
NewA2=A;
for k=1:numel(A)
Index=ismember(A{k},TP);
NewA2{k}(Index)=[];
end

更多回答（0 个）

类别

在 帮助中心 和 File Exchange 中查找有关 Logical 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by