integration- fzero error
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hi i am trying to do this:
fun=@(u,Q) u.*normcdf(u*Q,5,2);
k=quad(@(u) fun(u,Q),0,1);
p=3; r=10; h=6; cd=8; co=1;
f=@(Q) (p+r-h)*k-(p+r-cd)*0.5+co;
fzero(f,0)
But i keep getting these errors: ??? Undefined function or variable 'Q'.
Error in ==> @(u)fun(u,Q)
Error in ==> quad at 76 y = f(x, varargin{:});
Error in ==> newsvendor at 4 k=quad(@(u) fun(u,Q),0,1);
any ideas???
3 个评论
Torsten
2016-3-14
As I already mentionned, "quad" won't give you an integral expression that depends on Q. You will have to explicitly assign a value to Q before calling "quad":
fun=@(u,Q) u.*normcdf(u*Q,5,2);
Q=1;
k=quad(@(u) fun(u,Q),0,1);
Try "int" instead of "quad" to get a symbolic expression for k that depends on Q.
Best wishes
Torsten.
Nikos P
2016-3-14
Torsten
2016-3-15
So you used something like
syms Q x
k=int(x*normcfd(x*Q,5,2),x,0,1);
?
Best wishes
Torsten.
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