I'm afraid your chances for an answer are probably quite slim if you pose the question in French. I will answer in English for everybody else's sake and hope you understand this, otherwise the code should be understandable.
Just in case... Si mon Anglais n'est pas clair, j'espère que le code en bas sera suffisant pour résoudre le problème.
Basically, if I understand correctly, you need to do two steps:
1. Get the total row sum of each color section according to your percentages so that the total sum of each row is 2000. This step is simple, I'm sure you can figure it out.
2. Distribute this sum among the members
For example, let's say the desired sum of the red section of RM1 is SRM11 = 1200. Therefore SRM12, being the blue part, requires SRM12 = 800.
One possible (and I think intuitive) way would be:
SRM11 = 1200; % Total sum for red part in first row (1ère ligne, rouge)
SRM12 = 800; % Total sum for blue part in first row (1ère ligne, bleu)
X = zeros(4,6);
X(1,1) = randi(SRM11,1); % get the first number
SRM11 = SRM11 - X(1,1); % see how much is left to distribute
X(1,2) = randi(SRM11,1); % assign another random integer
X(1,3) = SRM11 - X(1,2); % get the rest to ensure the sum is correct
X(1,4) = randi(SRM12,1); % repeat
SRM12 = SRM12 - X(1,4);
X(1,5) = randi(SRM12,1);
X(1,6) = SRM12 - X(1,5);
etc.
It would be more elegant to write this in a for loop and perform the operation on all sections simultaneously, but I think the above example is clearer in how things work, and I will leave the rest as a little exercise.
Hope this helps.
Cheers
