Stegnaography using DCT
4 次查看(过去 30 天)
显示 更早的评论
this is the code we are using to implement steganography based on DCT....
I = imread('lena_std.jpg');
I = im2double(I(:,:,1));
I2=imread('test.bmp');
subplot(2,2,1),imshow(I);
subplot(2,2,2),imshow(I2);
I2=de2bi(I2(:,:,1));
x=reshape(I2',1,38400);
T = dctmtx(8);
dct = @(x)T * x * T';
B = blkproc(I,[8 8],dct);
k=0;
for i=1:256
for j=1:256
if B(i,j)>0
b=dec2bin(typecast(single(B(i,j)),'uint32'),32);
b(1,7:8)=x(1,k*2+1:k*2+2);
k=k+1;
c=double(typecast(uint32(bin2dec(b)),'single') );
B(i,j)=c;
end
end
end
subplot(2,2,3),imshow(B);
invdct = @(x)T' * x * T;
B3= blkproc(B,[2 2],invdct);
subplot(2,2,4),imshow(B3);
could somebody tell me the problem in this code with respect to the binary and decimal conversion....
2 个评论
采纳的回答
Walter Roberson
2012-1-30
You will find that de2bi() does not return the characters '0' and '1' that are required for bin2dec().
You will also find that the bit ordering is different between de2bi() and dec2bin(). Compare
dec2bin(8,5)
de2bi(8,5)
2 个评论
更多回答(5 个)
NILANJ
2013-4-19
I2=de2bi(I2(:,:,1)); can any one tell me plz that in this function why (:,:,1) ???
1 个评论
Peter Eze
2016-12-22
use transpose(dec2bin(ImageMessage(i,j))) to create the binary string for each pixel of the message to be embedded
0 个评论
juhi patel
2017-9-26
de2bi()is used for you want your data in matrix form.&dec2bin() is used if you want output in string format.you are mixing both function in this code.using de2bi() will solve your problem since image is in matrix form.
1 个评论
Walter Roberson
2017-9-26
I almost always use dec2bin() and subtract '0' to get matrix form. Then I do not have to worry about the fact that de2bi() is part of a communications toolbox rather than part of basic MATLAB.
Fady Samann
2020-6-13
编辑:Fady Samann
2020-8-12
First, you are not doing quantization to remove the samller DCT coefficients after that you can change LSB by masking it and and OR it with the message bit. Use bitwise operations, because dec2bin and bin2dec treat the binary as a string of 0's and 1's.
the process is just like JPG compression but in the middle of quantization and dequantization, you can change the LSB.
Second, when you pick the right DCT coefficient to change its LSB, the coefficient must be greater than one because of changing the LSB of one to zero (from the message bits) will set the coefficient to zero then during the decoding process this coefficient will be skipped because of the if condition (B(i,j)>0).
Note: round the number only after the quantization stage in the encoding and decoding of the message.
0 个评论
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Encryption / Cryptography 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!