Ouputting for loop into a matrix

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Tom Starley
Tom Starley 2011-3-8
Hi guys
I have a function called 'simulator' that has two inputs, Cl and Cd. The function outputs a Time around a circuit for these inputs.
I want to be able to execute a loop that runs a combination of Cls and Cds between 0 and 3, and to output all the resulting times into a matrix, and THEN to be able to find the smallest time and Matlab to tell me what time this is, and what Cl and Cd combination this was.
Has anyone any idea how to go about this code? So far I have...
for i=[0.1:0.1:3]; j=[0.1:0.1:3]; a=[1:1:30]; y(a)= simulator([(i) (j)]) end
But I'll be honest, it doesn't really work at all...
Many thanks in advance guys!
Tom

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回答（2 个）

Vieniava
Vieniava 2011-3-8
Try this:
Ci=0.1:0.1:30;
Cd=0.1:0.1:30;
y=zeros(numel(Ci), numel(Cd));
for i=1:numel(Ci)
for j=1:numel(Cd)
y(i,j)=simulator([ Ci(i) Cd(j) ]);
end
end
imagesc(y)
[v i]=min(y);
[II JJ]=ind2sub(size(y), i);
sprintf('The smallest time %f is for Ci=%f and Cd=%f', v,Ci(II),Cd(JJ))
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Tom Starley
Tom Starley 2011-3-8
The problems being that it's printing loads of different times, and it's taking values for Cd and Ci in excess of 400 when I want all possible of combinations of Ci and Cd when Ci=[0.1:0.1:3] and Cd=[0.1:0.1:3]
Many thanks!
Jan
Jan 2011-3-8
Simpler finding of minimal value using linear indexing:
[v, ind] = min(y(:));
sprintf('The smallest time %f is for Ci=%f and Cd=%f', v, Ci(ind), Cd(ind));

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Paulo Silva
Paulo Silva 2011-3-8
y=zeros(1,30);
i=[0.1:0.1:3];
j=[0.1:0.1:3];
for pos=1:numel(i)
y(pos)=simulator([i(pos) j(pos)])
end
fprintf('The minimum time was %d for i=%d and j=%d',min(y),i(y==min(y)),j(y==min(y))

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