coordinates of region segmented

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sbei arafet 2016-3-20

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https://ww2.mathworks.cn/matlabcentral/answers/274496-coordinates-of-region-segmented

评论： Image Analyst 2016-3-20

Hi,

I'm trying to recuperate coordinates of region segmented by fuzzy connectedness algorithm to use the foreground and the background as new seeds for the segmentation by the graph cut algorithm so the foreground will be the source and the background the sink , the problem that when i try to get new seeds it returns the first seeds chosen for fuzzy connectedness algorithm here is the source code

   FC=afc(S,K);%Absolute FC
        u=FC>thresh;
        v=FC<thresh;
        s=regionprops(u, 'PixelIdxList');%listes de pixels de l'objet
        t=regionprops(v, 'PixelIdxList');%listes de pixels de l'arrière plan
        [a,b]=size(s);
        [w,c]= size(t)
        for i=1:a
           for j=1:b
                [y,x] = ind2sub(size(u), s(i,j).PixelIdxList);
           end
       end
       for k=1:w
           for d=1:c
              [y1,x1] = ind2sub(size(v), t(k,d).PixelIdxList);
           end
       end

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Answer 1

Image Analyst 2016-3-20

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https://ww2.mathworks.cn/matlabcentral/answers/274496-coordinates-of-region-segmented#answer_214329

To get the x,y coordinates, don't do all that stuff with ind2sub() because regionprops() gives you the coordinates directly. Just ask regionprops() for PixelList instead of PixelIdxList.

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sbei arafet 2016-3-20

编辑：sbei arafet 2016-3-20

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Thanks for the ansewer i've tried PixelList but it gives the same resulat , so i tried

[x, y]=find(FC(:)>thresh)
[x1,y1]=find(FC(:)<thresh)

it gives the result but with a little problem seeds defined for the first segmentation are defined as background seed for the second segmentation as you can see,the green region aquire the red seeds wich are ues as foreground seeds for the first segmentation,i'll be grateful if have an idea about what could cause this problem

Image Analyst 2016-3-20

在 MATLAB Online 中打开

You've made a very, very common mistake that beginners usually make. In fact, so far, this is the second time I've had to correct people just today. You've swapped x and y. The syntax for find is NOT

[x, y] = find(signal);

It is

[rows, columns] = find(signal);

or equivalently

[y, x] = find(signal);

I'm not sure what else you're doing and possibly doing wrong but make that correction and see if it fixes things.

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