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Efficient splitting of strings

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Hamad Alsayed
Hamad Alsayed 2016-3-21
评论： Hamad Alsayed 2016-3-21
I have a cell array of strings which I would like to split into sub-arrays as follows:
Suppose a date-time cell array reads as:
inputArray =
'20150316 07:20:39:380941'
'20150317 07:20:39:380941'
'20150318 07:20:39:380941'
'20150319 07:20:39:380941'
I would like the output to be
outputArray =
'20150316'
'20150317'
'20150318'
'20150319'
Currently I am doing it by
outputArray = cellfun(@(x) x(1:8),inputArray,'uni',false);
which works just fine, however for inputArray into the millions of elements, this process is slow.
Is there a more efficient method which can perform the above? I know for sure that the structure of the strings in the array is fixed (i.e. the string length is always 24 and the first 8 elements are YYYYMMDD).

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KSSV
KSSV 2016-3-21
You can read all the strings into a character matrices and extract what you want. Example:
k = ['20150316 07:20:39:380941'
'20150317 07:20:39:380941'
'20150318 07:20:39:380941'
'20150319 07:20:39:380941'];
k(:,1:9)
Have you tried this?
  1 个评论
Hamad Alsayed
Hamad Alsayed 2016-3-21
That is perfect, Siva. Thank you. Even after "cellstr"-ing the answer back, execution time is cut by more than a half. Thanks again! Hamad.

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