How do I create a 3D histogram for; x = 1*26, y=1*28, z = 26*28 ?

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I would basically like to bin the the 'z' data into ranges of x and y such as the attached picture:
  2 个评论
Aaron Rampersad
Aaron Rampersad 2016-3-22
I used this code from filexchange but I ended up with a very dense plot attached below:
What I would like to do is place these z-values which is a 26*28 matrix into bins associated with the x and y values


回答(3 个)

Walter Roberson
Walter Roberson 2016-3-21
There are also a lot of histogram programs in the File Exchange.

Image Analyst
Image Analyst 2016-3-22
Aaron, give the x and y data as an N by 2 array, then pass in the number of bins in each direction into the poorly named hist3() to create your 2D histogram
counts = hist3([x, y], [26, 28]);
  8 个评论
Image Analyst
Image Analyst 2016-3-26
Well now you'r totally confusing everybody. We though that the x and y were basically ranges that your data could take. So one data point had both an x coordinate, and a y coordinate. And you wanted 28 bins along the y direction, and 26 bins along the x direction. And then "z" would be the counts of how many data points fell into a certain x,y bins. You don't have any z data yet, before taking the histogram, do you? It's to be computed and is the "count" data. If that's not right, then no one has read your mind correctly, and you'll need to explain better and attach your x, y, and z arrays.


Mike Garrity
Mike Garrity 2016-3-22
If you're using R2015b or later, you can use the new histogram2 function.
  13 个评论



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