Undefined Function or Variable but the variable is in fact Defined

Douglas Johnson

2016 3 21

1 个回答

回答已采纳

9 次查看（30 天）

显示更早的评论

0 个投票

So clearly k is defined, but Matlab keeps telling me it is not defined. What is going on?

>> k=1
       k =
           1
  >> f_n
        f_n = 
           @(r,n)sqrt(pi/(2*k*r))*besseli(n+.5,k*r)
    >> f_n(1,1)
             Undefined function or variable 'k'.
           Error in @(r,n)sqrt(pi/(2*k*r))*besseli(n+.5,k*r)

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

请先登录再关注

采纳的回答

Sean de Wolski 2016-3-21

1 个投票

The function was defined before k. When the anonymous function is created, it grabs a static snapshot of the workspace and does not update. To incorporate k, just rerun the command to create the function handle.