Can regexprep be used for partial text replacements containing special characters?

1 次查看（过去 30 天）
Brad
Brad 2016-3-25
评论： Azzi Abdelmalek 2016-3-25
I have a text file containing the following 3 lines of data:
"028 2016 10:11:12.12345" 39.028469 -104.484128 2070
"028 2016 10:11:13.1234" 39.028404 -104.484111 2075
"028 2016 10:11:14" 39.028390 -104.484000 2080
I am attempting to use regexprep to replace the time stamp portion (in quotations) with a single numerical value. If successful, the 3 lines of data would look like this:
1 39.028469 -104.484128 2070
2 39.028404 -104.484111 2075
3 39.028390 -104.484000 2080
I'm looking for a reference in the MATLAB documentation that would indicate how to account for the quotation marks, as well as all characters between them. This is my first attempt at using regexprep and I'm not even sure this is possible.
Is there a way to utilize regexprep for this instance?
Thank you.

请先登录，再回答此问题。

采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2016-3-25
编辑：Azzi Abdelmalek 2016-3-25
v=importdata('file.txt')
a=regexprep(v,'\<".+"\>','')
b=regexp(a,'\S+','match')
n=numel(b);
out=[(1:n)' str2double(reshape([b{:}],n,[]))]
  3 个评论
显示 1更早的评论
Azzi Abdelmalek
Azzi Abdelmalek 2016-3-25
Another alternative is
v=importdata('fic.txt')
w=num2cell(1:numel(v))'
a=cellfun(@(x,y) regexprep(x,'\<".+"\>',num2str(y)),v,w,'un',0)

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Characters and Strings 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by