suppressing output from user defined function
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function f=fib(n);
f=ones(n,1);
for i=1:n-2;
f(i+2,1)=f(i+1,1)+f(i,1);
end;
i have this function to calculate fibbonaci sequence, but i get outputs despite having semicolons on everything.
Can anyone tell me why?
采纳的回答
Jonathan Chin
2016-3-25
2 个投票
When you call your function use a semi colon at the end of the function to suppress the output.
try f=fib(n) and f=fib(n); in the command line to see the results
更多回答（1 个）
Walter Roberson
2016-3-25
You have to put a semi-colon in the line that calls fib() to prevent the default output
abc = fib(19)
fib is called and returns an expression that is assigned to the variable, but the default action for assignment is to also display the result of the assignment. You would need
abc = fib(19);
to suppress it.
This is not under the control of the called function, which does not have control by the time MATLAB makes the decision about whether to output or not.
5 个评论
Michael
2016-3-25
Yevgeniy Gorbachev
2024-2-25
That's not the case, though. plot has an output (`Line` object) but does not display it by default. Clearly there is some way to suppress the output from the callee. I'm currently trying to do that for some custom plotting functions and I can only find answers like this.
X = 1;
Y = 2;
custom_func(X,Y) % no output: no output shown
Z = custom_func(X,Y); % 1 output, suppressed with semicolon: output not shown
Z = custom_func(X,Y) % 1 output, unsuppressed: output shown
function out = custom_func(x,y)
result = x+y;
if nargout
out = result;
end
end
Yevgeniy Gorbachev
2024-2-25
@Voss Exactly the behavior I'm looking for, thank you!
Voss
2024-2-25
You're welcome!
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