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suppressing output from user defined function

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Michael
Michael 2016-3-25
评论： Voss 2024-2-25
function f=fib(n);
f=ones(n,1);
for i=1:n-2;
f(i+2,1)=f(i+1,1)+f(i,1);
end;
i have this function to calculate fibbonaci sequence, but i get outputs despite having semicolons on everything.
Can anyone tell me why?

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采纳的回答

Jonathan Chin
Jonathan Chin 2016-3-25
When you call your function use a semi colon at the end of the function to suppress the output.
try f=fib(n) and f=fib(n); in the command line to see the results

更多回答（1 个）

Walter Roberson
Walter Roberson 2016-3-25
You have to put a semi-colon in the line that calls fib() to prevent the default output
abc = fib(19)
fib is called and returns an expression that is assigned to the variable, but the default action for assignment is to also display the result of the assignment. You would need
abc = fib(19);
to suppress it.
This is not under the control of the called function, which does not have control by the time MATLAB makes the decision about whether to output or not.
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