Help with calculating median of an array without using built in function?

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Martin Kao
Martin Kao 2016-3-26
评论： DGM 2023-9-27
A=[8 6 7 5 3 0 9]
b=sort(A)
b= 0 3 5 6 7 8 9
Now what are the next steps?

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采纳的回答

Roger Stafford
Roger Stafford 2016-3-26
Next step:
n = length(b);
t = (n+1)/2;
md = (b(floor(t))+b(ceil(t)))/2; % <-- median
  2 个评论
Martin Kao
Martin Kao 2016-3-26
Thank you so much! What would the steps look like if there were an even number of terms?
Roger Stafford
Roger Stafford 2016-3-26
Same formula works for odd and even numbers:
1. even, say, n = 10, t = (10+1)/2 = 5.5, floor(t) = 5, ceil(t) = 6,
md = (b(5)+b(6))/2 (average of middle two values)
2. odd, say, n = 13, t = (13+1)/2 = 7, floor(7) = 7, ceil(7) = 7,
md = (b(7)+b(7))/2 = b(7) (center value)

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更多回答（2 个）

Azzi Abdelmalek
Azzi Abdelmalek 2016-3-26
use n=numel(A) to get the number of element in A. If n is odd, the median will be b((n+1)/2), if n is even, try to find out.
William
William 2023-9-27
Heres a quicker way:
sortedvec = sort(vec)
l = length(sortedvec)
x = (l + 1) / 2
median = sortedvec(x)

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