How to join character
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I have a string, after preprocessing i get result as
str=Institution/College
Name;
When i split the string using
str1=regexp(str, '/', 'split')
i get result as [1x11 char] [1x11 char]
str2{2}
gives
College
Name
i need as College Name, i need in one line as College Name
Kindly help
回答（3 个）
Image Analyst
2016-3-27
Well don't split it then. Or is the word Institution followed by a slash there and you just want to get rid of that?
str = 'Institution/College Name';
slashLocation = strfind(str, '/');
newStr = str(slashLocation+1:end) % Gives 'College Name'
6 个评论
Pat
2016-3-27
Image Analyst
2016-3-27
You don't get the same problem, with College in one cell and Name in another cell. I actually tried it before I posted. Nonetheless, you can use John D'Errico's allwords(), which I use all the time. http://www.mathworks.com/matlabcentral/fileexchange/27184-allwords
str = 'Department/Institution/College Name';
caWords = allwords(str, '/')
caWords =
'Department' 'Institution' 'College Name'
You supply some sentence or string and it splits it into separate cells according to what you say the delimiter is.
Pat
2016-3-27
Image Analyst
2016-3-27
编辑：Image Analyst
2016-3-27
I don't know what preprocessing you did to produce bdroot, and then I don't what find_system() does to bdroot. Why don't you simple use the code I gave you? It works, doesn't it, whereas your code doesn't.
Walter Roberson
2016-3-28
find_system does not split the subsystem names at blanks. It returns a cell array of strings, each with one name. The adjacent entries do not belong together.
It sounds to me as if you have a carriage return (or newline) in a subsystem name. Historically that was not permitted. If it is permitted now, then the carriage return (or newline) would be part of the name and so the name should not be merged onto one line.
Walter Roberson
2016-3-28
It appears that under some conditions, spaces and newlines are now permitted; http://www.mathworks.com/help/simulink/ug/accessing-signal-logging-data.html#budgyrh . However, they would still be part of the name. It would be valid to have a signal named 'College Name' (with a space) and a signal named ['College' char(10) 'Name'] (with a newline) in the same block, so putting them on the same line would be misrepresenting the name.
>> old = sprintf('Institution/College\nName')
old = Institution/College
Name
>> new = regexp(regexprep(old,'\s+',' '),'/','split');
>> new{:}
ans = Institution
ans = College Name
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2016-3-28
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