How do I simplify my trignometric matrices??

3 次查看（过去 30 天）
Yasir
Yasir 2016-3-30
回答： Star Strider 2016-3-30
I have tried using "simplify" command. MATLAB simplifies it to some extent but not completely. The code is as below:
if true
%clc
clear all
syms o l1 l2 l0;
A=[ cos(o) -sin(o) 1;
cos(o-120) -sin(o-120) 1;
cos(o-240) -sin(o-240) 1;
]
X=inv(A)
W=simplify(X)
end
The anwer of the first element of matrix "W" is shown as
if true
% -(sin(o - 120) - sin(o - 240))/(2*sin(120) - sin(240))
end
clearly which can be further simplified (by applying formulas of Sin(a-b)) to give answer of Cos(o)... What am I doing wrong here??
  1 个评论
Torsten
Torsten 2016-3-30
First of all, replace 120 by 2/3*pi and 240 by 4/3*pi (sin and cos work with radians, not with degrees).
Best wishes
Torsten.

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Star Strider
Star Strider 2016-3-30
Tell the simplify function to keep working on it:
W=simplify(X, 'steps', 20)
Also, as Torsten mentioned, the Symbolic Toolbox trigonometric functions require their arguments be in radians not degrees, so multiply the constants by ‘pi/180’.

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Number Theory 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by