Problem with the mean of index

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Sophia
Sophia 2016-3-30
编辑： Sophia 2016-3-30
% tr(i,j,ni) is 361*361*432
t_r = zeros(361,361,35);
ind=10:16;
for t=1:(ni/12)-1;
if t<=34
* *mean_tr* = mean(tr(i,j,ind));*
t_r(i,j,t) = mean_tr;
ind = ind + 12;
else
end
end
mean_winter_sid = mean(t_r,3);
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Star Strider
Star Strider 2016-3-30
Could it possibly be that:
mean(tr(i,j,ind))
are zero?
For example:
q = mean([-3:3])
q =
0.0000e+000
Sophia
Sophia 2016-3-30
I tried
ind = 10:16;
mean_tr = mean(tr(i,j,ind));
*It is showing zeros, but this should not be the case*

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采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2016-3-30
You can calculate the mean without a for loop
A=rand(361,361,432);
mina=mean(A(:)) % the mean off all the matrix
min1=mean(A,1); % dimension 1
min2=mean(A,2); % dimension 2
min3=mean(A,3); % dimension 3
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Sophia
Sophia 2016-3-30
编辑：Sophia 2016-3-30
Its working , thanks Azzi
ind=10:16;
for t=1:(ni/12)-1;
if t<=34
a = tr(1:361,1:361,ind);
mean_tr = mean(a,3);
t_r(:,:,t) = mean_tr;
ind = ind + 12;
else
end
end

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更多回答（1 个）

Chad Greene
Chad Greene 2016-3-30
Do the values of indices i and j ever change?
Can you describe in words what you are trying to do? I have a feeling it can be done much more simply and efficiently without loops.
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Sophia
Sophia 2016-3-30
I have a 361*361*432 matrix that describes the 361*361 size monthly images for 36 years.. So i have 432 matrices, i am trying to find the average over just the winter months, say Oct to April (10:16)

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