hello sir i want to calculate mean square error for my all possible value for the system how to calculate it ?
1 次查看(过去 30 天)
显示 更早的评论
k0=1;
ss=[0,1,2,3];
kk=0;
poss=[];
for ii=1:d
poss=[poss,k0+(ii-1)*(N/d)];
end
for ii=1:length(poss)
k1=poss(ii);
for jj=ii+1:length(poss)
k2=poss(jj);
kk=kk+1;
k_p(kk,:)=[k1,k2];
A=[1, 1 ; exp(1i*2*pi)*(k1-1)*(ss(2)/N), exp(1i*2*pi)*(k2-1)*(ss(2)/N) ;exp(1i*2*pi)*(k1-1)*(ss(3)/N) , exp(1i*2*pi)*(k2-1)*(ss(3)/N); exp(1i*2*pi)*(k1-1)*(ss(4)/N), exp(1i*2*pi)*(k2-1)*(ss(4)/N)];
XF=pinv(A)*XD(:,1)
1 个评论
Walter Roberson
2016-4-1
Your code is not complete. Some end statements are missing.
What is the mean squared error to be calculated relative to? MSE is used for comparison between two things, not by itself.
What are the parts that are allowed to vary for consideration of "all possible values"? I see that d is not defined so should we take it that f is one of the things that can change?
采纳的回答
Image Analyst
2016-4-1
There is a function immse() in the Image Processing Toolbox. But like Walter says, you need two signals.
3 个评论
Image Analyst
2016-4-3
That would be zero. The MSE of X as compared to X (itself) is, of course, zero.
更多回答(0 个)
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!