Yavuz
In this question you have only 3 points, but you may need more.
The function combinator.m is really useful when the amount of points increases, copy of combinator.m following these lines.
You mention in your question that you need the combinations with repetition. With 3 points makes 6:
combinator(3,2,'p')
=
2 1
1 2
3 1
1 3
3 2
2 3
However, since you are calculating distances you don't really need to calculate 6 distances, but just 3, because distance 1-2 is same as 2-1 and so on, then you need:
combinator(3,2,'c')
=
1 2
1 3
2 3
The answer starts here:
amount_points=3
amount_dist=numel(combinator(amount_points,2,'c'))/2 % how many distances to calculate for each round
[szA1 szA2]=size(A)
amount_observations=szA1 % how many rounds
distance=zeros(amount_observations,amount_dist) % make room for result
pair=combinator(amount_dist,2,'c') % all point pairs
for k=1:amount_observations
for j=1:amount_dist
distance(k,j)=(A(k,pair(j,1)).^2+A(k,pair(j,2)).^2).^.5
end
end
If you find this answer of any help solving your question, please click on the thumbs-up vote link,
thanks in advance
John
EDIT: copyright code removed
