function to solve a binary matrix?

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If i have a binary matrix (NxM)

A =[0 0 1 0 1 0 1 0 1 0 1 0 1 0 0 1
1 1 0 1 1 1 1 1 1 1 1 0 1 0 1
1 0 1 0 0 0 0 0 0 0 1 1 1 1 1
1 0 1 1 1 0 0 0 0 0 1 1 1 1 1
1 1 1 1 0 1 0 0 1 1 1 1 1 0 1
0 1 1 0 1 1 0 1 1 1 0 1 0 0 1
1 0 0 1 0 1 1 1 1 0 1 1 1 0 1
1 1 1 1 1 1 1 1 1 1 1 1 1 0 0
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
0 0 0 0 1 1 1 1 1 0 0 0 0 0 1];

I need a function to calculate number of 1 and in each row and put it in a new matrix like this

B = [ 1 1 1 1 1 1 1
8 1 1
1 5
3 5
1 5 1
2 3 1 1
1 4 3 1
      13

1 ]

And a third matrix for a column like this

C = [ 1 4 2 4 2 1 2 1 2 1 2 4 1 4 2 7
      1 3 2 2 2 1 6 4 5 6 2 3 7 3 1 2
          2   3 1         2
              3                       ]

Note when the counter see zero then the counter will be stop and start again for example [0 1 1 0 1 1 1 1 1 ] then the solution will be [2 5]

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Answer 1

Azzi Abdelmalek 2016-4-1

在 MATLAB Online 中打开

0 个投票

A =[0 0 1 0 1 0 1 0 1 0 1 0 1 0 0 1
  0 1 1 0 1 1 1 1 1 1 1 1 0 1 0 1
  1 1 0 1 0 0 0 0 0 0 0 1 1 1 1 1
  0 1 0 1 1 1 0 0 0 0 0 1 1 1 1 1
  0 1 1 1 1 0 1 0 0 1 1 1 1 1 0 1
  0 0 1 1 0 1 1 0 1 1 1 0 1 0 0 1
  0 1 0 0 1 0 1 1 1 1 0 1 1 1 0 1
  0 1 1 1 1 1 1 1 1 1 1 1 1 1 0 0
  1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
  0 0 0 0 0 1 1 1 1 1 0 0 0 0 0 1]
[n,m]=size(A);
B=(m+repmat(1:m,n,1)-A.*cumsum(A,2)).*A;
for k=1:n
  a=B(k,B(k,:)~=0);
  [~,~,kk]=unique(a);
  row1{k,1}=accumarray(kk,1);
end
celldisp(row1)