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find if there are more then 10 consecutive NaN values

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Oliver Kumar
Oliver Kumar 2016-4-4
评论： Image Analyst 2018-11-16
Hello
I have a 170 x 1 matrix. Whicht contains 1 and 0 values. 1 is for NaN. I have 170 of this matrices. Is there a way how i can find only the matrices which contain more the 10 consecutive NaN values?
For example I have the following:
A = [ 0 0 1 1 1 1 1 1 1 1 1 1 1 0]
B = [ 1 1 1 1 0 0 1 1 0 1 1 1 1 1]
Now I need a code that gives the solution A, so I now in A are more the 10 consecutive NaN values.
Thanks for your help. Oliver

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采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2016-4-4
编辑：Azzi Abdelmalek 2016-4-4
A = [ 0 0 1 1 1 1 1 1 1 1 1 1 1 0]
ii=strfind([0 A 0],[0 1])
jj=strfind([0 A 0],[1 0])
idx=max(jj-ii)
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更多回答（3 个）

Image Analyst
Image Analyst 2016-4-6
Another 2 line solution:
% Create sample data:
A = [ 0 0 1 1 1 1 1 1 1 1 1 1 1 0 0 1 1 1 1 1 1 1 1 1 1 1 1 0]
% Measure the lengths of each "run" of ones:
measurements = regionprops(logical(A), 'Area');
theLengths = [measurements.Area]
Andrei Bobrov
Andrei Bobrov 2016-4-5
i1 = find(diff([0 A 0]) == 1);
out = i1(find(diff([0 A 0]) == -1) - i1 > 10);
Prashant Dwivedi
Prashant Dwivedi 2018-11-16
Hello, My problem is similer .
I wantedt to consicutive non NaN values . I tried
regionprops for ~isnan.
It does not work .
Any help will appreciated .
Thank you.
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Prashant Dwivedi
Prashant Dwivedi 2018-11-16
编辑：Prashant Dwivedi 2018-11-16
I tried like this :-
clear all
A = [ 2 5 6 2 nan nan nan 3 4 3 5 5 3 nan nan 2 2 3 4 5 5 nan 2 4 nan 4 5 5 6]
% Create sample data:
% Measure the lengths of each "run" of ones:
Mnan = regionprops(logical(A), 'Area');
theLengths = [Mnan.Area];
% Measure the lengths of each "run" of ones:
Mval = regionprops(logical(~isnan(A)), 'Area');
theLengths = [Mval.Area];
knan = length(Mnan)
kval = length(Mval)
But it gives error
Error using logical
NaN's cannot be converted to logicals.
Error in test (line 7)
Mnan = regionprops(logical(A), 'Area');

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