Storing data from a for loop in a matrix

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CJ
CJ 2016-4-7
评论： Ced 2016-4-7
Just getting started with Matlab and am running into some issues. I need to store the ouput from each step of the For Loop in a matrix. The following is my code:
% Set initial paramters.
Cl_initial=3;
R=0.5;
u=0.5;
Clt=0;
% Solve for Cl residual.
for t=[68.92 109.97 287.22 116.95 171.89 90.3 103.54];
Clt=[t; Cl_initial*(1-R)/(1-R*exp(-u*t))];
end
The way I have it set up now only saves the very last calculation in the matrix. Any help would be appreciated!

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Ced
Ced 2016-4-7
编辑：Ced 2016-4-7
Hi
There is a search feature in the forum, you will find hundreds of examples for this.
But your problem is that you are overwriting Clt in each iteration. The solution is to save each iteration in a new column (or row). Generally speaking, it is always good to pre-initialize data containers (in this case a matrix) before filling it in a loop.
Something like:
% Set initial paramters.
Cl_initial=3;
R=0.5;
u=0.5;
t=[68.92 109.97 287.22 116.95 171.89 90.3 103.54];
Nt = length(t);
Clt = zeros(2,Nt);
% Solve for Cl residual.
for i = 1:Nt
Clt(:,i) = [ t(i) ; Cl_initial*(1-R)/(1-R*exp(-u*t(i)))];
end
  2 个评论
CJ
CJ 2016-4-7
I now see what I was missing. Thanks for the quick response.
Ced
Ced 2016-4-7
Sure. You can "accept" the answer to close the topic if your problem was solved. Thanks!

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更多回答（1 个）

Azzi Abdelmalek
Azzi Abdelmalek 2016-4-7
Cl_initial=3;
R=0.5;
u=0.5;
Clt=[];
% Solve for Cl residual.
for t=[68.92 109.97 287.22 116.95 171.89 90.3 103.54]
Clt=[Clt;t Cl_initial*(1-R)/(1-R*exp(-u*t))]
end

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