Command to reshape matrix diagonally

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fr_sk
fr_sk 2016-4-8
评论： Andrei Bobrov 2016-4-8
Hi, i'd like to transform
X = 1 100 40
2 107 30
3 90 50
4 120 60
into
Y = 1 100 40 3 90 50
2 107 30 4 120 60
I thought
Y = reshape(X,2,6)
would do the trick but it didn't give me the matrix I was looking for.
Any quick ideas will be appreciated.
Thanks!

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采纳的回答

Andrei Bobrov
Andrei Bobrov 2016-4-8
编辑：Andrei Bobrov 2016-4-8
% X - array with size [5541888 x 7]
% m2 - number of rows in second array, m2 = 1536
[~,n] = size(X);
out = reshape(permute(reshape(X',n,m2,[]),[1 3 2]),[],m2)';
or
[m,n] = size(X);
a = mat2cell(X,m2*ones(m/m2,1),n);
out = [a{:}];
  2 个评论
fr_sk
fr_sk 2016-4-8
This is the perfect solution, it works like charm!!! Thank you so much!
Just so I understand what you did: What does [1 3 2] do in this case? Also why X' instead of X ?
Andrei Bobrov
Andrei Bobrov 2016-4-8
rewrite on separate commands:
[~,n] = size(X);
a = reshape(X',n,m2,[]);
b = permute(a,[1 3 2]);
out = reshape(b,[],m2)';
Please read about MATLAB functions: ' - transpose, reshape, permute.

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更多回答（1 个）

Rick Rosson
Rick Rosson 2016-4-8
Y = [ X(1:end/2,:) X(end/2+1:end,:) ];
  1 个评论
fr_sk
fr_sk 2016-4-8
Wow, thanks a lot for the fast response. This works very well for this example. My actual dataset has the dimensions of 5541888 x 7, which I want to stack according to your method to obtain a 1536 X 25256 matrix.
I wanted to apply your idea, but then I realized that I have to enter the code for each column manually. Do you think there is a way to do it for these dimensions?

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