I would like to make an equation to solve t when T_max is equal to 450
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OC=[3/5;3/5*sqrt(3);0]
BC=[9/40*sqrt(3);27/40;9/20]
OB=OC+BC
R=OB
syms t
F=[0;0;t]
MO=cross(R,F)
OA=[0;1.2;0.9]
OAe=OA/norm(OA)
Max=dot(OAe,MO)*OAe
T_max=norm(Max)
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回答(2 个)
Roger Stafford
2016-4-13
编辑:Roger Stafford
2016-4-13
It is simple division:
t = 450/dot(OAe,cross(R,[0;0;1])); (<-- Corrected)
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sam0037
2016-4-13
Hi,
Appending these three commands to your code will do the magic:
eqn = T_max == 450;
res = solve(eqn,t);
val = double(res); %this is the desired value of t
Here are the documentation links for the same:
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