Matlab code help on Euler's Method

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Sanjida Ahmed
Sanjida Ahmed 2016-4-11
评论： Ahmed J. Abougarair 2024-3-20
I have to implement for academic purpose a Matlab code on Euler's method(y(i+1) = y(i) + h * f(x(i),y(i))) which has a condition for stopping iteration will be based on given number of x. I am new in Matlab but I have to submit the code so soon. I am facing lots of error in implementing that though I haven't so many knowledge on Matlab. If anyone provide me so easy and simple code on that then it'll be very helpful for me. Thank you.
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Muhammad Tahir
Muhammad Tahir 2023-12-24
移动：Dyuman Joshi 2023-12-26
y'=2x-3y+1, y(1)=5, y(1.2)=? MATLAB code using euler'method to obtain a four decimal and h= 0.1

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James Tursa
James Tursa 2016-4-11
Here is a general outline for Euler's Method:
% Euler's Method
% Initial conditions and setup
h = (enter your step size here); % step size
x = (enter the starting value of x here):h:(enter the ending value of x here); % the range of x
y = zeros(size(x)); % allocate the result y
y(1) = (enter the starting value of y here); % the initial y value
n = numel(y); % the number of y values
% The loop to solve the DE
for i=1:n-1
f = the expression for y' in your DE
y(i+1) = y(i) + h * f;
end
It is based on this link, which you have already read:
http://www.mathworks.com/matlabcentral/answers/224319-euler-method-without-using-ode-solvers
You need to fill in the values indicated, and also write the code for the f line. What is the DE you are trying to solve?
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ATUL
ATUL 2023-3-10
how many iterations, we will decide in this?
Ahmed J. Abougarair
Ahmed J. Abougarair 2024-3-20
% Euler's Method
% Initial conditions and setup
clc
clear
h = input('Enter your step size here :'); % step size
x = input('Enter the starting value of x :');
xend = input('Enter the ending value of xend :'); % the range of x
n = (xend-x)/h; % the number of y values
y = zeros(1,n); % allocate the result y
y(1) = input('Enter the starting value of y :'); % the initial y value
% The loop to solve the DE
for i=1:n
f(i) = 6- 2*(y(i)/x(i)); % dy/dx = 6-2y/x
y(i+1) = y(i) + h * f(i);
x(i+1)=x(i)+h;
end
[x' y']

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更多回答（2 个）

mahmoud mohamed abd el kader
h=0.5;
x=0:h:4;
y=zeros(size(x));
y(1)=1;
n=numel(y);
for i = 1:n-1
dydx= -2*x(i).^3 +12*x(i).^2 -20*x(i)+8.5 ;
y(i+1) = y(i)+dydx*h ;
fprintf('="Y"\n\t %0.01f',y(i));
end
%%fprintf('="Y"\n\t %0.01f',y);
plot(x,y);
grid on;
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James Tursa
James Tursa 2021-3-3
编辑：James Tursa 2021-3-3
@shireesha myadari Please delete this comment and open up a new question for this.
Ahmed J. Abougarair
Ahmed J. Abougarair 2024-3-20
% Euler's Method
% Initial conditions and setup
clc
clear
h = input('Enter your step size here :'); % step size
x = input('Enter the starting value of x :');
xend = input('Enter the ending value of xend :'); % the range of x
n = (xend-x)/h; % the number of y values
y = zeros(1,n); % allocate the result y
y(1) = input('Enter the starting value of y :'); % the initial y value
% The loop to solve the DE
for i=1:n
f(i) = 6- 2*(y(i)/x(i)); % dy/dx = 6-2y/x
y(i+1) = y(i) + h * f(i);
x(i+1)=x(i)+h;
end
[x' y']

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Rakshana
Rakshana 2022-11-13
h=0.5; x=0:h:4; y=zeros(size(x)); y(1)=1; n=numel(y); for i = 1:n-1 dydx= -2*x(i).^3 +12*x(i).^2 -20*x(i)+8.5 ; y(i+1) = y(i)+dydx*h ; fprintf('="Y"\n\t %0.01f',y(i)); end %%fprintf('="Y"\n\t %0.01f',y); plot(x,y); grid on;

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