Algebric Loop with FIR Filter in Simulink

2 次查看（过去 30 天）
Muhammad Kamran
Muhammad Kamran 2016-4-11
评论： Ced 2016-4-12
Hi, I have FIR filter and I put it in a feedback. It has some feed foward coefficient so it gives an Algebric Loop error. How i can solve it?
Regards,

请先登录，再回答此问题。

回答（1 个）

Ced
Ced 2016-4-11
By feedforward, do you mean a feedthrough in your filter? Two possibilities I can think of:
1. Incorporate your feedforward as a gain, i.e. instead of having y = u + a*y, write y = u/(1-a). This is the exact solution.
2. As a quick fix, you can include a memory or delay element. This shifts everything by one time step though.
  5 个评论
显示 3更早的评论
Muhammad Kamran
Muhammad Kamran 2016-4-12
I am also facing another problem now.
The filter equation is y[n] = (a0 + a1*z^(-1)+ a2*z^(-1) +...) x[n]
If put it in a feedback loop with H =1; then it will be not easy to make the form you suggested. I have attached the picture of it.Now the path through a0 will give algebraic loop error.
your help is really appreciated. Thanks for looking into my problem
Ced
Ced 2016-4-12
I think it's still possible. Your system is something like y = (a0 + a1*z^(-1) + ... )*(r-y), where r is that signal coming from the left.
So, extracting the feedthrough term, taking it to the other side and then dividing the whole equation by (1+a0), you get
y = r*a0/(1+a0) + (r-y)*(a1*z^(-1) + ... )*a0/(1+a0)
Note that the a0/(1+a0) gain will be before the +- sign. The feedthrough of r doesn't have to be extracted if you don't want to, but this way, you only have one filter block. Otherwise, you need two blocks (one without feedthrough for y (in the feedback) and one with feedthrough for r).
Alternative: You could try and set an initial condition block on the feedback. Otherwise, even with discrete time, simulink arrives at your feedback point, but has no way of knowing what value to expect because nothing has been computed yet.

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Adaptive Filters 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by