plotting points with different colors

2016 4 22
2 个回答
更新时间：2016 4 23
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Hi,
I have a MxM matrix RegionsMap whose components are integer numbers between 1 and 4. The element RegionsMap(k,j) represents a point in the complex plane, x(k)+i*y(j) (x and y are vectores I previously defined). I want to plot every one of these complex numbers in the complex plane in such a way that: If RegionsMap(k,j) is 1 I color the associated point in blue, if it is 2 I color the associated point in red,...etc (green and yellow for 3 and 4).
How can I achieve this? Any help will be appreciated! Thanks

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回答（2 个）

J. Webster
J. Webster 2016-4-22

1 个投票

something like this maybe?
RegionsMap = randi([1 4],10,10);
x = rand(1,10);
y = rand(1,10);
figure(10);
hold on;
for i=1:10
for j=1:10
switch RegionsMap(i,j)
case 1
plot(x(i),y(j), 'ob');
case 2
plot(x(i),y(j), 'or');
case 3
plot(x(i),y(j), 'og');
case 4
plot(x(i),y(j), 'oy');
end
end
end
hold off;

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Diego Soler Polo
Diego Soler Polo 2016-4-22
编辑：Diego Soler Polo 2016-4-22
This answer is very nice, thank you very much! I didn't know that switch command. There remains a little trouble: in my case, the number of different cases is an input (which can be as big as 10). I stated the question as I did just to simplify matters a little bit. Perhaps there's some way around this? Less importantly, but also more desirable en my case: can one make a plot like this but with solid circles? This gives a plot consisting of empty circles. Thank you.
J. Webster
J. Webster 2016-4-23
to fill in the circle, you can replace the plot command with
scatter(x(i),y(i), 'og', 'filled')
If you know there will be at most 10 possibilities, you could just define 10 different cases.
Or you could do like Walter Roberson noted and define a colormap.
Scatter plot documentation

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Walter Roberson
Walter Roberson 2016-4-23

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scatter() fourth parameter can be a vector of values. Create a colormap with as many entries as values you have. caxis([1,n]) where n is the number of entries. Now value K will be drawn with color from entry #K

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