How can i make the sum of matrix elements>0 under the condition that there are min 3 zeros between the sums?

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hdiba 2016-4-23

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评论： hdiba 2016-5-4

I hava a matrix: a=[2 3 0 0 4; 0 0 0 0 0; 0 5 3 0 4; 14 4 0 1 1; 0 0 0 0 0; 0 0 0 7 9; 0 0 0 0 0; 0 0 0 0 0; 9 6 0 0 1; 1 1 1 0 0];

How can i make the sum of elements>3, under the condition that there are at least 3 zeros between the last element of one and the first element of the next sum?

Output should be: E=[9 32 16 19]

thanks!

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Azzi Abdelmalek 2016-4-23

How did you get this result?

Image Analyst 2016-4-23

Next sum? Why is there more than one sum??? Looks like you need to read this before you fix your post.

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采纳的回答

Azzi Abdelmalek 2016-4-23

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/280618-how-can-i-make-the-sum-of-matrix-elements-0-under-the-condition-that-there-are-min-3-zeros-between-t#answer_219148

编辑：Azzi Abdelmalek 2016-4-23

在 MATLAB Online 中打开

a=[2 3 0 0 4; 0 0 0 0 0; 0 5 3 0 4; 14 4 0 1 1; 0 0 0 0 0; 0 0 0 7 9; 0 0 0 0 0; 0 0 0 0 0; 9 6 0 0 1; 1 1 1 0 0]
b=reshape(a',1,[]);
id=~b;
ii=strfind(id,[1 1 1 0])+2;
ii=[0 ii numel(b)];
for k=1:numel(ii)-1
  out(k)=sum(b(ii(k)+1:ii(k+1)));
end
out

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hdiba 2016-4-24

but the sums are not row sums. this was just an assumption you've done in the comment above.

hdiba 2016-5-4

is there any way to get the number of elements in a sum? maybe somehow with the difference between the end position and beginning position of the sum? in our example for sum 9=2+3+0+0+4, there are 5 summands

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