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How to add rows to a mtrix following a certain condition?

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Anderson
Anderson 2016-4-26
编辑： Anderson 2016-4-28
Suppose the following matrix r= [0; 1; 1.5; 1.6; 2; 10.4; 15.5].
How to add rows which are in the interval floor(r):0.1:floor(r)+1?
In the end, the output should be:
r_out = [0; 0.1; 0.2; ...; 1; 1.1; 1.2; ...; 2; 2.1; ...; 3; 10; 10.1; ...; 11; 15; 15.1; 15.2 ; ...; 16]
I have tried the following:
for i=1:size(r,1); p = floor(r(i)):0.1:floor(r(i))+1; q = [r; p']; end
However, it does not cover all the elements. Probably, the loop is erasing previous computation after each update.
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Anderson
Anderson 2016-4-26
编辑：Anderson 2016-4-26
No, this is absolutely not a homework!
I have tried the following:
for i=1:size(r,1); p = floor(r(i)):0.1:floor(r(i))+1; q = [r; p']; end
However, it does not cover all the elements. Probably, the loop is erasing previous computation after each update.
Anderson
Anderson 2016-4-26
I found the problem.
r=unique(r, 'rows', 'stable');
for i=1:size(r,1); p(i,:) = floor(r(i)):0.1:floor(r(i))+1; end
q = unique(reshape(p,[],1));

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回答（2 个）

Fangjun Jiang
Fangjun Jiang 2016-4-26
r= [0; 1; 1.5; 1.6; 2; 10.4; 15.5];
rf=unique(floor(r));
r_out=bsxfun(@plus,rf.',(0:0.1:1).');
r_out=r_out(:);
The output is slightly different than what you listed. The difference is the elements of [2:0.1:3]. Not sure which one should be correct based on your post.
Anderson
Anderson 2016-4-26
I found the problem.
r=unique(r, 'rows', 'stable');
for i=1:size(r,1); p(i,:) = floor(r(i)):0.1:floor(r(i))+1; end
q = unique(reshape(p,[],1));

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