Find function - index by rows?

2016 4 27
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更新时间：2016 4 27
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For the find function, I noticed that it indexes downward column by column. Is there a way to make it so that it indexes left to right row by row?

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Stephen23
Stephen23 2016-4-27
Nope. Transpose your data and start thinking in terms of columns, not rows.

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回答（2 个）

Azzi Abdelmalek
Azzi Abdelmalek 2016-4-27

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Apply find function to the transpose of your matrix
find(A'==2) % for example

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Eric Tran
Eric Tran 2016-4-27
Is there a way to do it without changing the orientation of the matrix. I'm trying to find the indices for "marching band member positions" and I want to try "moving" members one at a time down a row. With how the find function works now, the members are moving one at a time down a column and I'm running into some issues with that method, so I want to see how doing so with rows would affect my desired output.
Azzi Abdelmalek
Azzi Abdelmalek 2016-4-27
You are not changing your Matrix, your are just operating on another Matrix which is A'

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Andrei Bobrov
Andrei Bobrov 2016-4-27
编辑：Andrei Bobrov 2016-4-27

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Example:
A = rand(15) > .4; % your array
[i0,j0] = find(A);
c = num2cell(sortrows([i0,j0],1),1);
[i_out,j_out] = c{:};
or jast (as by Azzi)
[j_out,i_out] = find(A.');

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