You came close to answering it yourself. There is an any funciton.
Experiment with this to see if it does what you want:
Matrix = [0 1 4; 4 1 3];
y = Matrix;
for x = 1:10;
logic = any(x + y == 5)
end
EDIT — To see the results of the comparison for different values of ‘x’, tweak the code to store the values, and display them in an array:
Matrix = [0 1 4; 4 1 3];
y = Matrix;
for x = 1:10;
logic(x) = nnz(any(x + y == 5));
end
Result = [[1:10]', (logic > 0)']
Result =
1 1
2 1
3 0
4 1
5 1
6 0
7 0
8 0
9 0
10 0
