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i have a 42*16384. how do i average it so that i get a new matrix of size 42*2048 (if N=2048 represents one revolution and N=16384 represents 8 revolutions).

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Andrei Bobrov
Andrei Bobrov 2012-2-6

1 个投票

data - your array [42x16384]
EDIT
out = mean(reshape(data,size(data,1),[],8),3);
eg:
data - your array [55x72000]
out = mean(reshape(data,size(data,1),[],3),3);
or
out = squeeze(mean(reshape(data,size(data,1),3,[]),2)) ;

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Lisa Justin
Lisa Justin 2012-2-6
thanks. Please how do i do the same with a matrix of 55*72000 so i get 55*24000 (where N=24000 represents one revolution and N=72000 represents 3 revolutions)?
Andrei Bobrov
Andrei Bobrov 2012-2-6
out = mean(reshape(data.',size(data,2),[],3),3).'
Lisa Justin
Lisa Justin 2012-2-6
i get an error message
??? Error using ==> reshape
Product of known dimensions, 216000, not divisible into total number of elements,
3960000.
Lisa Justin
Lisa Justin 2012-2-6
I am still getting the same error message with
out = squeeze(mean(reshape(data.',size(data,2),8,[]),2)).'
Andrei Bobrov
Andrei Bobrov 2012-2-6
see EDIT

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