How to do this coding for this equation?

8 次查看（过去 30 天）
Fairuz Ridwan
Fairuz Ridwan 2016-5-1
评论： Fairuz Ridwan 2016-5-16
i=25/50001*sin100t+2/100*cos100t+Ce^-2t,
t=0

请先登录，再回答此问题。

采纳的回答

Walter Roberson
Walter Roberson 2016-5-1
syms C t
eqn = i == 25/50001*sin(100*t)+2/100*cos(100*t)+C*exp(-2*t);
eqn0 = subs(eqn,t,0);
solve(eqn0, C)
  7 个评论
显示 5更早的评论
Walter Roberson
Walter Roberson 2016-5-16
The above code is the solution for that.
Remember, i is the imaginary unit, http://www.mathworks.com/help/matlab/ref/i.html, the square root of negative 1. You have defined a value for the left side of the equation, sqrt(-1), and you have defined a t value, 0. Your equation comes evaluates down to sqrt(-1) = 1/50 + C . There is a single C that solves that equation, C = -1/50 + sqrt(-1) . That leads to a single point on the plot.
Fairuz Ridwan
Fairuz Ridwan 2016-5-16
Oh, I see that's mean C just the constant. Thanks for your help sir. Really appreciate.

请先登录，再进行评论。

更多回答（1 个）

louis rassinfosse
编辑：louis rassinfosse 2016-5-1
Try to use the symbolic toolbox;
syms t
I=.....
t=...
And you should get an answer

类别

在 Help Center 和 File Exchange 中查找有关 Mathematics 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by