How to do this coding for this equation?

 采纳的回答

syms C t
eqn = i == 25/50001*sin(100*t)+2/100*cos(100*t)+C*exp(-2*t);
eqn0 = subs(eqn,t,0);
solve(eqn0, C)

7 个评论

Thanks for the help.. But, exactly I have to plot the equation. Haha, I'm not sure how.. Will you help.
There is not much to plot. After the substitution of t being 0, you have one equation in one unknown (C), and that has a single solution. Your plot would be at most a single point on the complex plane.
Note: In MATLAB, i represents sqrt(-1)
Sorry sir, I have try to plot it but I don't get.. DO you know why?
syms C t
t0 = 0;
eqn = i == 25/50001*sin(100*t)+2/100*cos(100*t)+C*exp(-2*t);
eqn0 = subs(eqn,t,t0);
sol = solve(eqn0, C);
plot(real(sol), imag(sol), 'r*')
xlabel('real plane')
ylabel('imaginary plane');
The single red dot that results is the plot. The entire solution to the equation is:
C = - 1/50 + 1i
Sorry sir, the real task is I need to plot the equation (i=25/50001*sin100t+2/100*cos100t+Ce^-2t, t=0 ). This equation is the solution for a question. Then, I have to plot it by using matlab, I have try few code but the graph that I got just blank without plot. I'm not sure why because I'm still learning. Thanks for your help sir. If you have any idea?
The above code is the solution for that.
Remember, i is the imaginary unit, http://www.mathworks.com/help/matlab/ref/i.html, the square root of negative 1. You have defined a value for the left side of the equation, sqrt(-1), and you have defined a t value, 0. Your equation comes evaluates down to sqrt(-1) = 1/50 + C . There is a single C that solves that equation, C = -1/50 + sqrt(-1) . That leads to a single point on the plot.
Oh, I see that's mean C just the constant. Thanks for your help sir. Really appreciate.

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更多回答(1 个)

louis rassinfosse
编辑:louis rassinfosse 2016-5-1
Try to use the symbolic toolbox;
syms t
I=.....
t=...
And you should get an answer

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