Can someone help me with my if statements in my function?

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I have written this function for a homework assignment, Basically finding heronian isosceles triangles for a given Perimeter. My if statements
if ((b>= 2*a)) && ((b<=0));
continue
end
if IntTestA == 0
a=0; b=0; A=0;
continue
end
are not working properly I was wondering if someone could explain to me why.
  1 个评论
Jan
Jan 2016-5-1
编辑:Jan 2016-5-1
This is not twitter - tags do not need hash characters.
Before we can explain, why the code is not working "properly", we have to know, what you call "poperly". Note that all information we have is the "failing" code. And this code does exactly what its lines commands it to do. Due to the absence of comments, guessing your intention is risky.

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采纳的回答

Jos (10584)
Jos (10584) 2016-5-1
I quickly see three issues:
  1. a is always positive so b can never be both positive (>=2*a) and negative (<= 0).
  2. for A = sqrt(...) is a loop over a single value
  3. setting the iterator in a loop (a=0) does not effect the loop. See this example
for k=1:5
disp(k)
k = 5 ;
disp(k)
end
  1 个评论
Scott
Scott 2016-5-2
Thanks, I used elseif instead of && for P and b conditions and dropped the second point the question asked that the function output [0,0,0] if It does not satisfy Area as an integer. Maybe I just do not understand function output and how to alter it... Overall it's working now :) Just need to work out how to frintf 4 values P,a,b,A

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更多回答(1 个)

Roger Stafford
Roger Stafford 2016-5-1
Your test “IntTestP==0” does not accomplish what you think it does. The only way “fix((fix(P)-P)+1)” can be zero is for P to be a positive non-integer, and the further requirement that P<=0 is then impossible which means that the error message can never be issued.
  1 个评论
Scott
Scott 2016-5-1
编辑:Scott 2016-5-2
Thanks, you are right, I hadn't tested the integer test yet. :) Made the change below and it is working. if (IntTestP == 0); disp('error, input is not a non negative integer') elseif (P <= 0); disp('error, input is not a non negative integer') and it works as intended.

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