Automatic naming of matrix

Question

Jake 2016-5-2

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https://ww2.mathworks.cn/matlabcentral/answers/282186-automatic-naming-of-matrix

评论： Walter Roberson 2016-5-2

Hi,

I have a cell matrix of 300,000 x 100 format. By using for loops, I want to make a new matrix every 10,000 rows while naming each different matrix automatically. For instance, a matrix that contains 1:10,000 from the original huge matrix will have something like matrix_1 as follows:

matrix_1 = [1:10,000,:];
matrix_2 = [10,001:20,000,:];
.
.
.
.
matrix_20 = [190,001:200,000,:];

Would you mind sharing your thoughts on this?

Thanks for your help in advance!

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Answer 1

Azzi Abdelmalek 2016-5-2

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编辑：Azzi Abdelmalek 2016-5-2

在 MATLAB Online 中打开

This is not good, Use instead a cell array

matrix{1} = [1:10];
matrix{2} = [1:20]

http://matlab.wikia.com/wiki/FAQ#How_can_I_create_variables_A1.2C_A2.2C....2CA10_in_a_loop.3F

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Jake 2016-5-2

在 MATLAB Online 中打开

Thanks Walter! This helps. However, I forgot to mention earlier that the original matrix that I have is based on text.file. So, after running script as you can see below, I have tmp = {284781x1 cell}, which is actually 53 columns (i.e. variables) existing within this cell structure format for each row.

fid = fopen(filename,'r');
tmp = textscan(fid,'%s','Delimiter','\n');

Given a suggested solution you mentioned above, I have 100,000 rows (1X411 char) in each matrix which is remaining a char format.

How can I break each row of char format and convert into cell matrix as a result?? Thus, I want to have a cell matrix of [100,000 x 53] instead of a char matrix of [100,000 x 1]...

Please share your thoughts. Thanks for your help again!!!