Automatic naming of matrix

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Jake
Jake 2016-5-2
评论： Walter Roberson 2016-5-2
Hi,
I have a cell matrix of 300,000 x 100 format. By using for loops, I want to make a new matrix every 10,000 rows while naming each different matrix automatically. For instance, a matrix that contains 1:10,000 from the original huge matrix will have something like matrix_1 as follows:
matrix_1 = [1:10,000,:];
matrix_2 = [10,001:20,000,:];
.
.
.
.
matrix_20 = [190,001:200,000,:];
Would you mind sharing your thoughts on this?
Thanks for your help in advance!

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Azzi Abdelmalek
Azzi Abdelmalek 2016-5-2
编辑：Azzi Abdelmalek 2016-5-2
This is not good, Use instead a cell array
matrix{1} = [1:10];
matrix{2} = [1:20]
http://matlab.wikia.com/wiki/FAQ#How_can_I_create_variables_A1.2C_A2.2C....2CA10_in_a_loop.3F
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Jake
Jake 2016-5-2
Thanks Walter! This helps. However, I forgot to mention earlier that the original matrix that I have is based on text.file. So, after running script as you can see below, I have tmp = {284781x1 cell}, which is actually 53 columns (i.e. variables) existing within this cell structure format for each row.
fid = fopen(filename,'r');
tmp = textscan(fid,'%s','Delimiter','\n');
Given a suggested solution you mentioned above, I have 100,000 rows (1X411 char) in each matrix which is remaining a char format.
How can I break each row of char format and convert into cell matrix as a result?? Thus, I want to have a cell matrix of [100,000 x 53] instead of a char matrix of [100,000 x 1]...
Please share your thoughts. Thanks for your help again!!!

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