How to use if-then with matrix indices

4 次查看(过去 30 天)
Hi, I got a matrix n by n of a symbolic value a. And I want to change the value of a based on the matrix indices.
syms a
n=50;
z=ones(n)*a;
for i=1:1:n
for j=1:1:n
if j=1 or j=i then a=4
else a=8
Could you please help? thanks

采纳的回答

Guillaume
Guillaume 2016-5-3
You certainly don't need a loop to generate your a.
a = ones(n) * 8; %default value everywhere
[rows, cols] = ndgrid(1:n); %matrices of row and column indices
a(rows == 1 | rows == cols) = 4; %substitute when condition is met
Note that because your i and j variables are meaningless, it's not clear whether you meant it to be column 1 or row 1 that get sets to 4. I assume it was rows but it's obvious how to change it to columns. Using variable names with meaning makes the code much clearer. Moreover i and j are actually functions in matlab, so are not recommended as variable names anyway.

更多回答(2 个)

Andrei Bobrov
Andrei Bobrov 2016-5-3
编辑:Andrei Bobrov 2016-5-3
n = 50;
z = ones(n)*8;
z(:,1) = 4;
z(eye(n)>0) = 4;

Torsten
Torsten 2016-5-3
n = 50;
z = ones(n)*8;
z(:,1)=4;
z(eye(n)==1)=4;
Best wishes
Torsten.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by