How to avoid that loop
显示 更早的评论
k(1) = 1;
for i=2:size(k)
k(i) = k(i-1)*v(i)
end
v(i) is a scalar and it's different on every iteration How could I do that without using a loop?
2 个评论
the cyclist
2016-5-3
编辑：the cyclist
2016-5-3
As written, this loop will never be executed, because size(k) is 1, and
for i = 2:1
<stuff>
end
will have zero iterations.
Some coding mistake? Maybe you meant length(v)?
Alberto Menichetti
2016-5-3
采纳的回答
the cyclist
2016-5-3
If my speculation about what you meant it correct, then
k = cumprod(v)/v(1)
2 个评论
Alberto Menichetti
2016-5-3
Steven Lord
2016-5-3
No, we understand you. Another approach that doesn't involve division:
v = randperm(8) % Sample data for demonstration purposes
k = cumprod([1 v(2:end)])
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