addressing a cell array

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hiva
hiva 2016-5-6
评论： hiva 2016-5-6
i have a cell array like this: < 328,2 > cell named : fastaStrs all i want is to access all rows of the second column of this array. when i type "fastaStrs{:,2}" in command window, each row of the second column of my array is returned seperately. like this: ans: first row of the second column ans: second row of the second column... and so forth. but when i try to use the same syntax in my code,( i am trying to extract the cells containing numeric data from the second column) it doesn't work. ind = find(cellfun(@isnumeric,fastaStrs{:,2}) == 1); returns me this error: cellfun Input #2 expected to be a cell array, was char instead.
any body knows what i am doing wrong?

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采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2016-5-6
编辑：Azzi Abdelmalek 2016-5-6
s={1 'rt';2 'er';3 'tr';4 5 ;8 'zz';9 1}
a=s(:,2)
idx=cellfun(@(x) isequal(1,x),a)
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hiva
hiva 2016-5-6
thanks, it worked. really thanks..
CS Researcher
CS Researcher 2016-5-6
If it helped, please accept his answer. It will help others too!

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更多回答（1 个）

CS Researcher
CS Researcher 2016-5-6
How about this:
a = cell2mat(fastaStrs);
b = a(:,2);
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CS Researcher
CS Researcher 2016-5-6
Oh I assumed the entire cell array is of the same type. Can you share the cellarray?
hiva
hiva 2016-5-6
no it is a mixture of double and char types. but it is solved by Mr Azzi's solution: fastaStrs(:,2) thanks a lot for your caring.

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