Colored Hexagons using Patch

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0 个投票

Hi to everyone, I was trying to make a honeycomb with Matlab, I've had no problem with the structure but I've some trouble trying to colour those hexagons with some defined color (e.g. red, blue and violet). This is the way I get the hexagons:

theta=0:60:360;
x=sind(theta); 
y=cosd(theta);
v=x(2); 
for i=1:4; x=x+v*2; a(i,:)=x; b(i,:)=y; %Create the row
end
c=a'; d=b';
for j=1:4; e=d+1.5*j; re=rem(j,2); %Create the columns
  if re==0, g=c; 
  else g=c-v; 
  end
  colour=linspace(0,1,i)
  patch(g,e,colour)
end
hold on
patch(c,d,colour)

But the colour is not specified by me, but is randomly chosen from 0 to 1.

I've read the help but I don't get the point.

Thanks in advance to everyone!!

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Answer 1

Image Analyst 2016-5-6

在 MATLAB Online 中打开

0 个投票

Replace this:

colour=linspace(0,1,i)
patch(g,e,colour)

with this

% Define color with whatever values you need for the color you want.
colour=[1, 0.4, 0.5];  % Any 3 values between 0 and 1, or predefined colors 'r', 'b', 'y', etc.
patch(g,e,colour);

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Mike Garrity 2016-5-6

在 MATLAB Online 中打开

What I did in the blog post that picture came from was this:

cindex = 1+mod(2*mod(i,2) + 1*mod(j,2),7);

Did you try that? The basic idea is to have both your row index and column index go into generating the color.

stefano stefano 2016-5-7

在 MATLAB Online 中打开

I see your answer just now: I was inspired by your post on the blog and I want to try a 2-d version!

 theta=0:pi/3:2*pi;
x=sin(theta);
y=cos(theta);
v=x(2);
u=y(1)+y(2);
for i=1:columns;
    x=x+v*2;
    a(i,:)=x; b(i,:)=y;
    c=a'; d=b';
    r1=rem(i,2);
    if r1==0, col1(i)='r';
    else col1(i)='c';
    end
    axis equal
    patch(c(:,i),d(:,i),col1(i)); 
    for k=1:rows/2;
        g=d+3*k;
        patch(c(:,i),g(:,i),col1(i))
    end
end
for j=1:columns;
    e=c-v; f=d+u;
    r2=rem(j,2);
    if r2==0, col2(j)='y';
    else col2(j)='m';
    end
    patch(e(:,j),f(:,j),col2(j))
    for h=1:rows/2;
        l=f+3*h;
        patch(e(:,j),l(:,j),col2(j))
    end
end