How can i plot the response of function as a vector ?

Hi,
To resolve a secon order differential equation i do this function , but i have a problem when i want to plot xdot.
function xdot = equacte(t,x)
% Function file for mass with spring.
% Position is first variable, velocity is second variable,load is the third variable
freq=100; %frequency (Hz)
w=2*pi*freq;
m=0.0112;
k=262.8257 ;
teta =-4.40e+03;
cp= 1.8492*10^-7;
for rload =0:20:50000
A = [0,1,0;-k/m,0,-teta/m;(-teta/rload),0,-1/(rload*cp)];
B = [0;1/m;0];
f =sin(w*t);
xdot = A*x+B*f;
end
end
In the principle program :
[t,x]=ode45(@equacte,[0:0.0004:1],[0,0,0]);
xdot=equacte(t,x);
plot(t,xdot(:,1),'O',t,xdot(:,2),'r',t,xdot(:,3),'b');

 采纳的回答

What this line is doing? xdot=equacte(t,x) just write
[t,x]=ode45(@equacte,[0:0.0004:1],[0,0,0]);
plot(t,x(:,1),'O',t,x(:,2),'r',t,x(:,3),'b')

6 个评论

Now I noticed, the for loop inside your function is useless,
for rload =0:20:50000
A = [0,1,0;-k/m,0,-teta/m;(-teta/rload),0,-1/(rload*cp)];
B = [0;1/m;0];
f =sin(w*t);
xdot = A*x+B*f;
end
will produce the same effect as
rload =50000
A = [0,1,0;-k/m,0,-teta/m;(-teta/rload),0,-1/(rload*cp)];
B = [0;1/m;0];
f =sin(w*t);
xdot = A*x+B*f;
If you want to plot xdot:
xdot=diff(x)
plot(t,xdot(:,1),'O',t,xdot(:,2),'r',t,xdot(:,3),'b')
No, tis for loop is necessary. For each vlue of rload i want the value of x.
Ok, but like you did it, the loop has no effect, only the last value will be taken in account.
Your function should look like
function xdot = equacte(t,x,rload)
% Function file for mass with spring.
% Position is first variable, velocity is second variable,load is the third variable
freq=100; %frequency (Hz)
w=2*pi*freq;
m=0.0112;
k=262.8257 ;
teta =-4.40e+03;
cp= 1.8492*10^-7;
A = [0,1,0;-k/m,0,-teta/m;(-teta/rload),0,-1/(rload*cp)]
B = [0;1/m;0];
f =sin(w*t);
xdot = A*x+B*f;
end
Then call it in the loop
for rload=2000:20:2040
[t,x]=ode45(@(t,x) equacte(t,x,rload),[0 1],[0,0,0]);
figure;
plot(t(2:end-1),diff(x))
end

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