STRCAT SYNTAX TO BE USED?

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ck
ck 2016-5-7
编辑： Jan 2016-5-7
IF I WANT TO STRCAT 2 VALUES I WOULD DO STRCAT(S1,S2), SO WHAT IF I WANT TO DO N VALUES AND 'N' IS A VALUE WHICH GETS DEFINED IN BETWEEN THE PROGRAM?? WHAT IS THE SYNTAX I SHOULD USE?
THANK YOU
  1 个评论
Jan
Jan 2016-5-7
Please note that writing in uppercase means shouting in the forum. So please calm down and type your question as all otehr do with a proper case. Thanks.

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采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2016-5-7
N=3
str='abc'
out=repmat(str,1,N)

更多回答（1 个）

Jan
Jan 2016-5-7
编辑：Jan 2016-5-7
If you store a dynamical number of string, you do not use the names S1, S2, S..., but you store them in a cell string:
C = {'String 1', 'String 2', 'String 3'}; % and so on
Then instead of writing:
S = strcat(C{1}, C{2}, C{3})
You can write:
S = strcat(C{:});
This works with 200 million strings also, where names like S200000000 would be too ugly.
  2 个评论
ck
ck 2016-5-7
thanks!, so if I want to strcat the elements on matrix from a(1,1) to a(n,1) into another matrix b(1,1) how is that done?
Jan
Jan 2016-5-7
编辑：Jan 2016-5-7
@Chetan: You have selected Azzi's answer as a solution, but it performs something completely different. Accepting an answer means, that it solves your problem.
You cannot assign a vector with many elements to a scalar variable b. Storing strings in a CHAR-matrix has severe disadvantages, e.g. you cannot distinguish the padded spaces with trailing spaces, which belong to the strings. A conversion to a cell string removes the padded spaces:
S = char('hi', 'matlab', 'user');
C = cellstr(S);
B = strcat(C{:})
If you want to keep the spaces you do not need strcat:
B = reshape(S.', 1, [])

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