Replace elements meeting condition with last valid value

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Alonso
Alonso 2016-5-8
评论： Alonso 2016-5-9
I have lots of .mat files with a pair of vectors Pn and En, so I wrote a little fraction of it:
n=2;
S=[75 100];
P1=[22.38 29.84 44.76 59.78 75];
E1=[0.795 0.805 0.815 0.826 0.835];
P2=[45.90 68.86 91.81 114.76 130];
E2=[0.78 0.79 0.795 0.805 0.821];
for ef1=1:1:n
PTEfx=eval(sprintf('P%d',ef1));
ETEfx=eval(sprintf('E%d',ef1));
PTmax=max(eval(sprintf('P%d',ef1)));
ETmax=max(eval(sprintf('E%d',ef1)));
if PTmax>S(ef1)
for ef2=1:1:length(PTEfx)
ind(ef2)=PTEfx(ef2)>Sn(ef1);
PTEfx(ind)=[];
ETEfx(ind)=[];
end
end
PTEf(ef1,:)=PTEfx;
ETEf(ef1,:)=ETEfx;
end
I'm trying to create a matrix containing all those vectors, but I want to replace every element from Pn that's bigger than its corresponding value of S to the last value that is less or equal to it. In addition to this, vector En must have the same behavior. So, for this example the result should be:
PTEf=[22.38 29.84 44.76 59.78 75;
45.90 68.86 91.81 91.81 91.81]
ETEf=[0.795 0.805 0.815 0.826 0.835;
0.78 0.79 0.795 0.795 0.795];
I think I'm almost there, but I was only able to delete those bigger values and I don't want to fill the vector with 0's in order to fit in the matrix.
Suggestions?

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采纳的回答

Elias Gule
Elias Gule 2016-5-9
I guess I understand what you want to do. Try this
PTEf = [P1;P2];
ETEf = [E1;E2];
ij = PTEf>S(1) | PTEf > S(end);
PTEf(ij) = min(PTEf(ij));
ETEf(ij) = min(ETEf(ij));
  1 个评论
Alonso
Alonso 2016-5-9
In the end, I achieved what I wanted but with a much more longer code haha I guess I will change it. Another question: if in Pn and En, n can be modified (from 2 to 200), would you use a loop like:
for ef1=1:1:n
PTEf=eval(sprintf('P%d',ef1));
ETEf=eval(sprintf('E%d',ef1));
end
Thank you Elias

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