Help split a text file into 3 arrays (textscan)

2012 2 7
3 个回答
1 次查看（30 天）

0 个投票

Greatings, I am fairly new with importing text files and extracting what I need so any suggestions would be great. I have a text file as:
1 02/06/2012 10:55:43.109 23.580898 2 02/06/2012 10:55:43.109 23.431202 3 02/06/2012 10:55:43.109 23.081917 1 02/06/2012 10:55:43.750 23.580898 2 02/06/2012 10:55:43.750 23.431202 3 02/06/2012 10:55:43.750 23.081917
I am wondering if its possible to split this into:
1 02/06/2012 10:55:43.109 23.580898 1 02/06/2012 10:55:43.750 23.580898
Separating each group by the 1st column. I was thinking of implementing a while loop that would look like:
%Read First Line [a b]=strtok(fid) % Implement Logic command while a = 1 % Store in some cell Any suggestions would be great..

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回答（3 个）

RNTL
RNTL 2012-2-10

0 个投票

can you explain what is it exactly to you want to transform ? I couldn't understand it from the example you gave.
Lucas
Lucas 2012-2-10

0 个投票

Ah I see the problem the text file showed up wrong
1 02/06/2012 10:55:43.109 23.580898
2 02/06/2012 10:55:43.109 23.431202
3 02/06/2012 10:55:43.109 23.081917
1 02/06/2012 10:55:43.750 23.580898
2 02/06/2012 10:55:43.750 23.431202
3 02/06/2012 10:55:43.750 23.081917
This is what the text file looks like, with the exceptions of no spaces between the text. But I have figured out a way to read the text using a for loop (converting the 1,2,3 to a real number ) and stating
if a == 1
Do this
elseif a ==2
Do this ...etc
RNTL
RNTL 2012-2-10

0 个投票

if all you wish is every 3rd row, why not simply using indexing on what you have ?.. say Data is the name of the array you're describing above.
so co1_1 = data(1:3:end,:); col_2 = data(2:3:end,:); .. and so on

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Lucas
Lucas
2012-2-7

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