How to do this

Question

Ram k 2016-5-11

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关闭： MATLAB Answer Bot 2021-8-20

Suppose I have a sequence of n numbers

e=[5,4,45,63,22,22,1,12,3,2,2,16,14,14,16,17,1,19,21,15,32,32,27,27,43,41,7,8,13,23,23]

then for first 10 numbers i.e.

[5,4,45,63,22,22,1,12,3,2]

count numbers other than 1 to 5 and then divide by 10, i.e.

[45,63,22,22,12]

total 5, so result should be 5/10,now for first 20 numbers i.e.

[5,4,45,63,22,22,1,12,3,2,2,16,14,14,16,17,1,19,21,15]

then

[45,63,22,22,12,16,14,14,16,17,19,21,15]
total =13, so 13/20, like this for first 30,40,50...upto n numbers

and then plot figure with x axis points 0 10 20 30....n and y axis with 5/10,13/20..... how to do this

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Answer 1

Guillaume 2016-5-11

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编辑：Guillaume 2016-5-12

在 MATLAB Online 中打开

Have you tried using a loop? It would be very straightforward.

Alternatively:

e=[5,4,45,63,22,22,1,12,3,2,2,16,14,14,16,17,1,19,21,15,32,32,27,27,43,41,7,8,13,23,23]
countinout = accumarray([ceil((1:numel(e))/10); 2-(e>5)]', e, [], @numel);
ratioin = cumsum(countinout(:, 1)) ./ (1:size(countinout(:,1)))' ./ 10;
plot((0:numel(ratioin)-1)*10, ratioin)