Transpose single column onto a Geometry
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Hi, I have (26 x 1) W = 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46, and want to use X(26 x 2) which is the address matrix for G...
X =
2 2
3 2
4 2
2 3
3 3
4 3
2 4
3 4
4 4
2 5
3 5
4 5
2 6
3 6
4 6
2 7
3 7
4 7
2 8
3 8
4 8
2 9
3 9
4 9
2 10
3 10,
to transpose W onto: G =
-1 -1 -1 -1 -1 -1 -1 -1 -1 -1
-1 0 0 0 0 0 0 0 0 0
-1 0 0 0 0 0 0 0 0 0
-1 0 0 0 0 0 0 0 0 5
采纳的回答
Star Strider
2016-5-13
%Matrix size
columns=10;
rows=4;
%Blank matrix
X = zeros(4,10);
%Fill matrix (1st row & first column)
newrow =-ones(1,columns); % the row to replace row 1 with
newcolumn=-ones(rows,1); % the column to replace column 1 with
X(1,:)= newrow ; % replace row 1 in a with new
X(:,1) = newcolumn(:); % replace column 1 in a with new
zi = find(X == 0);
X(zi) = [W; 5]'
X =
-1 -1 -1 -1 -1 -1 -1 -1 -1 -1
-1 21 24 27 30 33 36 39 42 45
-1 22 25 28 31 34 37 40 43 46
-1 23 26 29 32 35 38 41 44 5
6 个评论
Aswas
2016-5-13
Star Strider
2016-5-13
Sure!
Replace the ‘X(zi)’ assignment with:
X(zi) = reshape([W' 5], [], 3)'
to produce:
X =
-1 -1 -1 -1 -1 -1 -1 -1 -1 -1
-1 21 22 23 24 25 26 27 28 29
-1 30 31 32 33 34 35 36 37 38
-1 39 40 41 42 43 44 45 46 5
Star Strider
2016-5-13
You have to change the size of the matrix you want reshape to produce. See if this works:
X(zi) = reshape([W' 5], [], 2)'
Here, I tell it to produce a matrix of 2 columns instead of 3 as before, then (as before) use the transpose operator (') to produce the 2-row matrix you want.
Note that the ‘5’ in the vector is the value you want at the end.
See the documentation for the reshape function for details on how to tell it to do what you want. It is versatile, but it has some necessary constraints.
Aswas
2016-5-13
Star Strider
2016-5-13
As always, my pleasure.
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