Matrix dimensions to create for loop?
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Hi all. I have rr(6x200) matrix. I want to find Rc and V matrixes for each 200 column, I showed below for one column:
Rc=toeplitz(rr(1:6)); %Rc(6x6)
V=Rc\eye(6,1); %V(6x1)
In the end, I need V matrix (6x200) but because of Rc is (6x6) matrix I could not create for loop.
1 个评论
Jos (10584)
2016-5-16
You meant R= toeplitz(rr(:,k)), where k runs from 1 to 200?
采纳的回答
I'm not sure why you can't use a loop:
V = zeros(size(rr));
denum = eye(size(rr, 1), 1); %so it's not recreated 200 times in the loop
for col = 1 : size(rr, 2)
Rc = toeplitz(rr(:, col));
V(:, col) = Rc \ denum;
end
Alternatively:
denum = eye(size(rr, 1), 1);
V = cell2mat(cellfun(@(col) toeplitz(col)\denum, num2cell(rr, 1), 'UniformOutput', false))
The loop is likely to be marginally faster.
更多回答（2 个）
Jos (10584)
2016-5-16
You can use a for-loop:
rr = rand(6,200) ;
[nr,nc] = size(rr) ;
X = eye(nr,1) ; % take it out of the loop
V = zeros(nr,nc) ; % pre-allocation
for k=1:nc % loop over columns
Rc = toeplitz(rr(:,k)) ;
V(:,k) = Rc \ X ;
end
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